As of PHP 5.3.0, you can use __DIR__ as a replacement for dirname(__FILE__)
PHP - Manual: dirname
2024-12-20
dirname
(PHP 4, PHP 5, PHP 7, PHP 8)
dirname — 返回路径中的目录部分
说明
dirname(string
$path, int $levels = 1): string
给出一个包含有指向一个文件的全路径的字符串，本函数返回去掉文件名后的目录名，且目录深度为 levels 级。
注意:
dirname() 纯粹基于输入字符串操作， 它不会受实际文件系统和类似 "
.." 的路径格式影响。
警告
dirname() 是本地化的，所以如果要正确处理多字节字符的路径，需要用 setlocale() 正确设置匹配的 locale。
参数
-
path -
一个路径。
在 Windows 中，斜线（
/）和反斜线（\）都可以用作目录分隔符。在其它环境下是斜线（/）。 -
levels -
要向上的父目录数量。
整型，必须大于 0。
返回值
返回 path 的父目录。
如果在 path
中没有斜线，则返回一个点（'.'），表示当前目录。否则返回的是把
path 中结尾的
/component（最后一个斜线以及后面部分）去掉之后的字符串。
更新日志
| 版本 | 说明 |
|---|---|
| 7.0.0 |
添加可选的 levels 参数。
|
范例
示例 #1 dirname() 例子
<?php
echo dirname("/etc/passwd") . PHP_EOL;
echo dirname("/etc/") . PHP_EOL;
echo dirname(".") . PHP_EOL;
echo dirname("C:\\") . PHP_EOL;
echo dirname("/usr/local/lib", 2);
以上例程的输出类似于：
/etc / (or \ on Windows) . C:\ /usr
add a note
User Contributed Notes 29 notes
y dot a dot dejong at singular dot of dot alumni dot utwente dot nl ¶
7 years ago
tapken at engter dot de ¶
20 years ago
To get the directory of current included file:
<?php
dirname(__FILE__);
?>
For example, if a script called 'database.init.php' which is included from anywhere on the filesystem wants to include the script 'database.class.php', which lays in the same directory, you can use:
<?php
include_once(dirname(__FILE__) . '/database.class.php');
?>
tobylewis at mac dot com ¶
16 years ago
Since the paths in the examples given only have two parts (e.g. "/etc/passwd") it is not obvious whether dirname returns the single path element of the parent directory or whether it returns the whole path up to and including the parent directory. From experimentation it appears to be the latter.
e.g.
dirname('/usr/local/magic/bin');
returns '/usr/local/magic' and not just 'magic'
Also it is not immediately obvious that dirname effectively returns the parent directory of the last item of the path regardless of whether the last item is a directory or a file. (i.e. one might think that if the path given was a directory then dirname would return the entire original path since that is a directory name.)
Further the presense of a directory separator at the end of the path does not necessarily indicate that last item of the path is a directory, and so
dirname('/usr/local/magic/bin/'); #note final '/'
would return the same result as in my example above.
In short this seems to be more of a string manipulation function that strips off the last non-null file or directory element off of a path string.
joe dot naylor at gmail dot com ¶
13 years ago
The dirname function does not usually return a slash on the end, which might encourage you to create links using code like this:
$url = dirname($_SERVER['PHP_SELF']) . '/somepage.php';
However dirname returns a slash if the path you specify is the root, so $url in that case would become '//somepage.php'. If you put that URL as the action on a form, for example, submitting the form will try to go to http://somepage.php.
I ran into this when I wrote a site on a url with a path, www.somehost.com/client/somepage.php, where the code above works great, but then wanted to put it on a subdomain, client.somehost.com/somepage.php, where things started breaking.
The best solution would be to create a function that generates absolute URLs and use that throughout the site, but creating a safe_dirname function (and an htaccess rewrite to fix double-slashes just in case) fixed the issue for me:
<?php
function safe_dirname($path)
{
$dirname = dirname($path);
return $dirname == '/' ? '' : $dirname;
}
?>
klugg this-is-junk at tlen dot pl ¶
16 years ago
Attention with this. Dirname likes to mess with the slashes.
On Windows, Apache:
<?php
echo '$_SERVER[PHP_SELF]: ' . $_SERVER['PHP_SELF'] . '<br />';
echo 'Dirname($_SERVER[PHP_SELF]: ' . dirname($_SERVER['PHP_SELF']) . '<br>';
?>
prints out
$_SERVER[PHP_SELF]: /index.php
Dirname($_SERVER[PHP_SELF]: \
ts at dev dot websafe dot pl ¶
14 years ago
Inside of script.php I needed to know the name of the containing directory. For example, if my script was in '/var/www/htdocs/website/somedir/script.php' i needed to know 'somedir' in a unified way.
The solution is:
<?php
$containing_dir = basename(dirname(__FILE__));
?>
Tom ¶
13 years ago
Expanding on Anonymous' comment, this is not necessarily correct. If the user is using a secure protocol, this URL is inaccurate. This will work properly:
<?php
// Is the user using HTTPS?
$url = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] == 'on')) ? 'https://' : 'http://';
// Complete the URL
$url .= $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']);
// echo the URL
echo $url;
?>
hans111 at yahoo dot com ¶
15 years ago
The same function but a bit improved, will use REQUEST_URI, if not available, will use PHP_SELF and if not available will use __FILE__, in this case, the function MUST be in the same file. It should work, both under Windows and *NIX.
<?php
function my_dir(){
return end(explode('/', dirname(!empty($_SERVER['REQUEST_URI']) ? $_SERVER['REQUEST_URI'] : !empty($_SERVER['PHP_SELF']) ? $_SERVER['PHP_SELF'] : str_replace('\\','/',__FILE__))));
}
?>
soywiz at hotmail dot com ¶
18 years ago
You can use it to get parent directory:
dirname(dirname(__FILE__))
...include a file relative to file path:
include(dirname(__FILE__) . '/path/relative/file_to_include.php');
..etc.
bobray at softville dot com ¶
3 years ago
Be aware that if you call dirname(__FILE__) on Windows, you may get backslashes. If you then try to use str_replace() or preg_replace() to replace part of the path using forward slashes in your search pattern, there will be no match. You can normalize paths with $path = str_replace('\\', '/' ,$path) before doing any transformations
iam at shaz3e dot com ¶
8 years ago
File located locally in: F:\localhost\www\Shaz3e-ResponsiveFramework\S3-CMS\_source
Localhost Path: http://s3lab.com/Shaz3e-ResponsiveFramework/S3-CMS/_source/
Example 1: dirname($_SERVER['PHP_SELF']); //output: /Shaz3e-ResponsiveFramework/S3-CMS/_source
Example 2: "http://".$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']); //output: http://s3lab.com/Shaz3e-ResponsiveFramework/S3-CMS/_source
Example 3: $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']); //output: s3lab.com/Shaz3e-ResponsiveFramework/S3-CMS/_source
nhl261 at yahoo dot com ¶
10 years ago
As usual, to include or require a file, we use this
<?php
require dirname(__FILE__) . DIRECTORY_SEPARATOR . 'my_file.php';
?>
in rare case, we have current file existing at the root directory, dirname would return C:\ or / , then the line above contains 2 slashes \\ or //
To handle this this case, we use rtrim to clear slashes.
<?php
require rtrim(dirname(__FILE__), '/\\') . DIRECTORY_SEPARATOR . 'my_file.php';
?>
Also, another use of dirname is to get virtual directory (url path), the issue is the same as above, we have to check and process before concatenating strings
frederikreiss at gmx dot de ¶
8 years ago
what about a recursive dirname. To get $count levels up in a directory.
<?php
function r_dirname($path, $count=1){
if ($count > 1){
return dirname(r_dirname($path, --$count));
}else{
return dirname($path);
}
}
Xedecimal at gmail dot com ¶
15 years ago
Getting absolute path of the current script:
<?php
dirname(__FILE__)
?>
Getting webserver relative path of the current script...
<?php
function GetRelativePath($path)
{
$npath = str_replace('\\', '/', $path);
return str_replace(GetVar('DOCUMENT_ROOT'), '', $npath);
}
?>
later on
<?php
GetRelativePath(dirname(__FILE__));
?>
If anyone has a better way, get to the constructive critisism!
Anonymous ¶
14 years ago
A simple way to show the www path to a folder containing a file...
echo "http://".$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']);
legolas558 dot sourceforge comma net ¶
15 years ago
The best way to get the absolute path of the folder of the currently parsed PHP script is:
<?php
if (DIRECTORY_SEPARATOR=='/')
$absolute_path = dirname(__FILE__).'/';
else
$absolute_path = str_replace('\\', '/', dirname(__FILE__)).'/';
?>
This will result in an absolute unix-style path which works ok also on PHP5 under Windows, where mixing '\' and '/' may give troubles.
[EDIT by danbrown AT php DOT net: Applied author-supplied fix from follow-up note.]
rudecoder at yahoo dot com ¶
19 years ago
dirname can be used to create self referencing web scripts with the following one liner.
<?php
$base_url = str_replace($DOCUMENT_ROOT, "", dirname($PHP_SELF));
?>
Using this method on a file such as:
/home/mysite/public_html/wherever/whatever.php
will return:
/wherever
Now $base_url can be used in your HTML to reference other scripts in the same directory.
Example:
href='<?=$base_url?>/myscript.php'
ken dot forslund at hp dot com ¶
13 years ago
A key problem to hierarchical include trees is that PHP processes include paths relative to the original file, not the current including file.
A solution to that, is to prefix all include paths with:
<?php str_replace('//','/',dirname(__FILE__)); ?>
this will generate a base path relative to the current file, which will then allow an include behavior similar to C/C++.
thus, to include a file that is 1 in the parent directory:
<?php require_once( str_replace('//','/',dirname(__FILE__).'/') .'../parent.php'); ?>
to include a file that is in the same directory:
<?php require_once( str_replace('//','/',dirname(__FILE__).'/') .'neighbor.php'); ?>
to include a file that is in a subdirectory:
<?php require_once( str_replace('//','/',dirname(__FILE__).'/') .'folder/sub.php'); ?>
Notice that all paths we reference must NOT begin with a /, and must be relative to the current file, in order to concatenate correctly.
minimalist at intelligence dot com ¶
10 years ago
If you want to get the parent parent directory of your script, you can use this:
<?php
//Example script path: home/content/en/script.php
$parentparentdir=basename(dirname(dirname(__FILE__)));
echo $parentparentdir; //will output 'content'
?>
webyazilimci84 at gmail dot com ¶
12 years ago
In my mvc based framework i make BASE_PATH and BASE_URL definitions like the following and both work well in the framework without problem.
index.php :
define('BASE_PATH',realpath('.'));
define('BASE_URL', dirname($_SERVER["SCRIPT_NAME"]));
BASE_PATH is for server side inclusions.
BASE_URL is for client side inclusions (scripts, css files, images etc.)
subzey at immelman dot ru ¶
11 years ago
In some situations (I can't locate the dependencies) basename and dirname may return incorrect values if parsed string is in UTF-8.
Like, dirname("glossary/задний-фокус") will return "glossary" and basename("glossary/задний-фокус") will return "-фокус".
Quickfix is
str_replace("!$!", "", dirname(str_replace("/", "!$!/!$!", $q)))
Zingus J. Rinkle ¶
14 years ago
Most mkpath() function I saw listed here seem long and convoluted.
Here's mine:
<?php
function mkpath($path)
{
if(@mkdir($path) or file_exists($path)) return true;
return (mkpath(dirname($path)) and mkdir($path));
}
?>
Untested on windows, but dirname() manual says it should work.
rmahase at gmail dot com ¶
14 years ago
this little function gets the top level public directory
eg. http://www.mysite.com/directory1/file.php
or http://www.mysite.com/directory1/directory2/directory3/file.php
will both return "directory1" ...which is the top level directory
<?php
function public_base_directory()
{
//get public directory structure eg "/top/second/third"
$public_directory = dirname($_SERVER['PHP_SELF']);
//place each directory into array
$directory_array = explode('/', $public_directory);
//get highest or top level in array of directory strings
$public_base = max($directory_array);
return $public_base;
}
?>
Holger Th?lking ¶
17 years ago
If you merely want to find out wether a certain file is located within or underneath a certain directory or not, e.g. for White List validation, the following function might be useful to you:
<?php
function in_dir ($file, $in_dir)
{
$dir = realpath ($file);
$in_dir = realpath ($in_dir);
if (!is_dir ($file)) {
$dir = dirname ($file);
}
do {
if ($dir === $in_dir) {
$is_in_dir = TRUE;
break;
}
} while ($dir !== ($dir = dirname ($dir)));
return (bool) @$is_in_dir;
}
?>
dave at corecomm dot us ¶
19 years ago
I very much appreciated Fredrich Echol's suggestion (rwf at gpcom dot net) of how to find a base path, but found that it failed when the initial script was already in the root folder -- dirname('/rootscript.php')=='/' and dirname('/include/includescript.php')=='/include' which have the same number of slashes. This variation is what I'm now using:
<?php
if (!defined("BASE_PATH")) define('BASE_PATH', dirname($_SERVER['SCRIPT_NAME'])=='/' ? './' : str_repeat("../", substr_count(dirname($_SERVER["SCRIPT_NAME"]), "/")));
?>
This explicitly checks for the root path (/) and uses './' as the base path if we're in the root folder.
I put this at/near the top of any file that calls another. (I used define for my own convenience; should work just fine with variables and without testing to see if you already did it.)
Note that in both cases (root-folder script and non-root-folder script), BASE_PATH will include a trailing slash. At least with Apache on Darwin (Mac OS X), you can include(BASE_PATH.'/myfile.php'); and the doubled slash won't cause any problems, giving the same result as include(BASE_PATH.'myfile.php'); .
andrey at php dot net ¶
19 years ago
Code for write permissions check:
<?php
error_reporting(E_ALL);
$dir_name = '/var/www/virtual/phpintra/htdocs/php/';
do {
$b_is_writable = is_writable($dir_name);
echo sprintf("Dir[%s]Writable[%s]\n", $dir_name, $b_is_writable? 'YES':'NO');
}while (($dir_name = dirname($dir_name)) !='/');
?>
Yousef Ismaeil Cliprz ¶
9 years ago
You can get best root path if you want to call a file from you project paths.
Make sure this define in your www/index.php
or the core file that inside www/ root.
<?php
/**
* @def (string) DS - Directory separator.
*/
define("DS","/",true);
/**
* @def (resource) BASE_PATH - get a base path.
*/
define('BASE_PATH',realpath(dirname(__FILE__)).DS,true);
?>
You can call any file any time without any problems
<?php
include BASE_PATH.'inc/class.php';
?>
qeremy (!) gmail ¶
6 years ago
After PHP 7;
<?php
print dirname("/usr/local/lib", 2); # /usr
?>
Before PHP 7;
<?php
print dirname(dirname("/usr/local/lib")); # /usr
# or
function dirname_with_levels($path, $levels = 1) {
while ($levels--) {
$path = dirname($path);
}
return $path;
}
print dirname_with_levels("/usr/local/lib", 2); # /usr
?>
renich at woralelandia dot com ¶
16 years ago
--- Edited by tularis@php.net ---
You could also have a look at the getcwd() function
--- End Edit ---
A nice "current directory" function.
function current_dir()
{
$path = dirname($_SERVER[PHP_SELF]);
$position = strrpos($path,'/') + 1;
print substr($path,$position);
}
current_dir();
I find this usefull for a lot of stuff! You can maintain a modular site with dir names as modules names. At least I would like PHP guys to add this to the function list!
If there is anything out there like it, please tell me.
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