HTTP 1.1 (RFC 2068) requires an RFC 1123 date with a four digit year, so the correct format to use for a Last-modified header would look something like this:
<?php
header("Last-modified: " .
gmstrftime("%a, %d %b %Y %T %Z",getlastmod()));
?>
PHP - Manual: gmstrftime
2024-12-23
(PHP 4, PHP 5, PHP 7, PHP 8)
gmstrftime — 根据区域设置格式化 GMT/UTC 时间/日期
$format
, int $timestamp
= ?): string和 strftime() 的行为相同,只除了返回时间是格林威治标准时(GMT)。例如,当在东部标准时(EST,GMT -500)运行时,下面第一行显示“Dec 31 1998 20:00:00”,而第二行显示“Jan 01 1999 01:00:00”。
示例 #1 gmstrftime() 例子
<?php
setlocale(LC_TIME, 'en_US');
echo strftime("%b %d %Y %H:%M:%S", mktime (20,0,0,12,31,98))."\n";
echo gmstrftime("%b %d %Y %H:%M:%S", mktime (20,0,0,12,31,98))."\n";
?>
参见 strftime()。
HTTP 1.1 (RFC 2068) requires an RFC 1123 date with a four digit year, so the correct format to use for a Last-modified header would look something like this:
<?php
header("Last-modified: " .
gmstrftime("%a, %d %b %Y %T %Z",getlastmod()));
?>
If you want the dutch time on your pages and you are hosted on a server in the USA you can easily change it this way:
<?php
setlocale(LC_TIME, 'nl_NL');
$tgl = gmstrftime("%d %B %Y - %H:%M uur",time()+3600);
?>
Then use $tgl to display the right time.
Note the +3600 is a day light savings time correction.
The result: 22 maart 2005 - 16:39 uur
First I used the normal date function and this was the previous result: March 22, 2005 - 04:28 AM
I needed it for a dutch guestbook.
I'm new to PHP and it took me a while to find it out and maybe it's of no use for experienced PHP programmers but I thought people can always ignore my post :)
To get a RFC 850 date (used in HTTP) of the current time:
gmstrftime ("%A %d-%b-%y %T %Z", time ());
This will get for example:
Friday 25-Jun-04 03:30:23 GMT
Please note that times in HTTP-headers _must_ be GMT, so use gmstrftime() instead of strftime().
gmstrftime() should not be used to generate a RFC 850 date for use in HTTP headers, since its output is affected by setlocale().
Use gmdate instead:
gmdate('D, d M Y H:i:s') . ' GMT';