date_sub

(PHP 5 >= 5.3.0, PHP 7, PHP 8)

date_sub — 别名 DateTime::sub()

说明

此函数是该函数的别名： DateTime::sub()

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User Contributed Notes 4 notes

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vitkor dot kruglikov at gmail dot com ¶

7 years ago


It can be unclear for someone how to use this function.
Here is the example:

$date=date_create("2013-03-15");
date_sub($date,date_interval_create_from_date_string("40 days"));
echo date_format($date,"Y-m-d");

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fpradove at gmail dot com ¶

4 years ago


In version 5.6.31 the variable $ today is passed by reference in the function date_sub () and the interval is also applied

<?php 
$today = date_create(date('Y-m-d'));
$yesterday = date_sub($today, date_interval_create_from_date_string("1 days"));

        echo var_dump($today);
        echo var_dump($yesterday)
?>

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-2

Thomas LEDUC ¶

7 years ago


To glue to the OOP, it's better to use it with DateInterval::createFromDateString

<?php 
$dateB = new DateTime('2020-12-20'); 
$dateA = $dateB->sub(DateInterval::createFromDateString('10 days'));
?>

more detail here :
<?php
public static function createFromDateString ($time) {}
?>

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-4

Jonathan Poissant ¶

11 years ago


You cannot replace date_sub('2000-01-20') by DateTime::sub('2000-01-20') because DateTime::sub is not static. You have to create the DateTime object first.


Example:


<?php $dateA = date_sub('2000-01-20', date_interval_create_from_date_string('10 days')); ?>



will be replace by

<?php

$dateB = new DateTime('2000-01-20');

$dateA = $dateB->sub(date_interval_create_from_date_string('10 days'));

?>

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官方地址：https://www.php.net/manual/en/function.date-sub.php

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date_sub

说明

User Contributed Notes 4 notes